bash scripting question

[seanmclemon]

i have the variable $filename which i'd like to strip of it's extension. i mean for example in perl i'd simply do

$filename =~ s/(.+?)\..*/$1/;

and that'd leave me with the name minus the extension. Has anyone any ideas about how i can do this with a bash script?

thanks,
-Sean

[pbharris]

hello,
this will rename anything with an extention of tmp to what ever it is w/o the .tmp extention - not sure why the *.* is not taking hold...

#!/bin/bash
for i in *.*
do
name=$(echo $i|sed 's/\.tmp$//')

[seanmclemon]

Works for me

Just a quick extension to the question...i only need to strip the types .ram and .rm, short of repeating the RE on the next line is there a way i can do this?
my weak attempt didn't seem to fly...

name=$(echo $i|sed 's/\.["ram"|"rm"]$//')

Try || or /

[seanmclemon]

ahh, never mind. Through use of consumate .'s (well one...) i managed.

name=$(echo $i|sed 's/\..*$//')

thanks for the help, pbharris
- Sean

[gorn]

perl can be used from the command line too:

foo=$(echo $i | perl -e 's/foo/bar/g&#039

[Hko]

You can also do this without any external program, using plain bash:

#!/bin/bash

tmp1="file1.ram"
tmp2="file2.rm"

shopt -s extglob

echo ${tmp1%.@(ram|rm)}
echo ${tmp2%.@(ram|rm)}

[gorn]

[quote author=Hko link=board=9;threadid=7681;start=0#msg70211 date=1062779536]You can also do this without any external program, using plain bash:[/quote]

very cool, i always thought calling sed seemed unneeded for something so simple, but it was usually quick scripts i'd never use again so i never really looked. thanks for the tip!