a script to give me the last argument !!!

[rameshvl]

Hi

I just want a shell script which gives me the last argument passed.

For example,
if the script script.sh is executed

>script.sh one two three

it must give me "three"

Also,

>script.sh one two "three four"

must give me "three four"

Could u geeks help me ??????

thanks in advance,
rameshvl

[Schotty]

Only if you send me a script that makes my PC brew good beer and shoot it out the useless floppy drive into my mug ;D

[trickster]

[quote author=rameshvl link=board=9;threadid=6893;start=0#64253 date=1051249815]
Hi

I just want a shell script which gives me the last argument passed.

For example,
if the script script.sh is executed

>script.sh one two three

it must give me "three"

Also,

>script.sh one two "three four"

must give me "three four"

Could u geeks help me ??????

thanks in advance,
rameshvl


[/quote]

You know, if you are looking for help, you might want to be more courteous... Calling people "geeks" is kind of rude.

[garskoci]

Did you even look or try anything?

Put this in a file and run it.

echo $3

[Mor_gath]

#!/bin/bash
ARGV=$*
echo $ARGV |awk '  {  printf(" \n %d and arg-1 %d ", $NF , $(NF-1) ); } '

$* is all arguments provided
there you go, NF is the number of records you can play with that.

bash scripting supports printf() - kewl, you learn something every day.

[Mor_gath]

yep, oh forgot to say if you ain't to good at coding %d = interget(number), %s (string).
you can also have if statements within awk so it's farily straightforward.

[quote author=trickster link=board=9;threadid=6893;start=0#64269 date=1051273494]

You know, if you are looking for help, you might want to be more courteous... Calling people "geeks" is kind of rude.
[/quote]

He meant geeks as in computer geeks and most people here I bet will call themselves geeks all the time and dont mind being called geeks, it's a badge of honor

[rameshvl]

exactly, thanks a lot, Mr. vlad902

Anyway, I found a simpler solution for my problem, let me share it with u all,

shift $(($# - 1))

will do the trick,
I can get the last argument with $1 after the above line

Thanks a lot to everyone who replied,

regards,
rameshvl

[demian]

The simplest would be to use the special variable !$ which always contains the last argument to the last command

This tip was brought to you by www.unixtips.org