1. ## Subnetting Question

Suppose the administrator of a class B IP network wishes to divide the network to create subnets with up to 240 hosts on each subnet. Then what would be a suitable net/host address boundary and a subnet mask.

My Solution:

240 host = log2(240) = 8

therefore there are 32 bits in ip address and we need the 8 bits to accommodate 240 hosts.

Therefore 32-8 = 24. Therefore we need the first 24 bits for the network park, which suggest the
host/net boundary of /24 is suitable.

This means that the first 24 bits are all 1s and therefore we get the following:
11111111 11111111 11111111 = 255.255.255.

Therefore our subnet mask becomes 255.255.255.0 with a boundary of /24 on class B IP network.

HI Can anybody check my solution and please let me know whether it is right or wrong.

Thank you

2. You can use at least 254 different networks, like so:

network 172.16.1.0/24

network 172.16.2.0/24

etc, etc.

In other words, you are on the right track.

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