loop with input file?

[sabre]

I have a file with a list of user names, such as

john
jan
test
dennis
etc...

I want to read in the account name, change the password parameters, then move on to the next name in the list.

A loop of course, but I can't figure out how to specify the input file, and how to read one name at a time.

Any ideas would be appreciated.

[Outlaw]

Quickly, since its almost miller time:

Assuming user.txt

[wayne@UW-GOODRICHWE ~]$ for i in `cat user.txt`; do echo $i.user; done
john.user
jan.user
test.user
dennis.user

#!/bin/bash
#
for i in `cat user.txt`
do
    echo "$i.luser"
done

That just shows the mechanics of the for loop. You want to actually perform an action on the value of $i in a bash script

[sabre]

Next I had to learn that ` does not equal '. Made an amazing difference! Thanks again.

[lel]

Hi Sabre,

I was wondering if you would mind helping me with a similar problem??
I have saved a file ...

[lg45@dev64-mgmt ~]$ cat table.txt

Angiogenin 10 25793633 25815393
Alpha-actinin 28 7893500 7941168

The example above (for i in `cat user.txt`; do echo $i; done) does not give me the same result and i am unsure why. instead i get the following:

[lg45@dev64-mgmt ~]$ for in in `cat table.txt`; do echo $i; done
table.txt
table.txt
table.txt
table.txt
table.txt
table.txt
table.txt
table.txt

I am trying to write a loop that will pull out column 2 in every line of table.txt, and allow me to modify it
Any suggestions would be appreciated

Thanks,
Lel

[lel]

Sorry - message is for outlaw...

[redhead]

#  for in in `cat table.txt`; do echo $i; done

It should be

# for i in `cat table.txt`; do echo $i; done

the misspelling makes a huge difference.

[lel]

Hi redhead - sorry that typo was fixed up but still does not give me the answer im looking for. It gives all the information in one column, when i require a loop through column 2.

[lel]

For more information, i have a file with 3 columns. ie

#Animal Start Stop
Dog 4 5
Cat 5 6
Owl 8 9

And i want to loop through file #2 and pull out all the lines with a start stop the same as file #1 above
ie the bolded lines

#Animal Start stop
monkey 1 2
monkey 2 3
monkey 3 4
monkey 4 4
monkey 5 6
monkey 6 8
monkey 7 9

[redhead]

Then you need to do it in some perl-scripting, bash script wouldn't be the tool for the job, when you need to compare several flags.

I'm guessing here, you need to filter file #2 and identify "Dog" there with a start=4 and filter any line between this and when reaching line "Dog" with a stop=5, am I right ?

[lel]

Thanks for the reply redhead, Thats right thats exactly what i am trying to do!!!
So i have written the following to define start and stop...

[lg45@dev64-mgmt ~]$ for i in `seq 1 7`; do start=`head -$i regions.txt | awk '{print $3}'`; done
[lg45@dev64-mgmt ~]$ start=`head -$i regions.txt | awk '{print $3}'`
[lg45@dev64-mgmt ~]$ echo $start
25293633 7393500 10578865 25293623 122206254 26797134 41906484
[lg45@dev64-mgmt ~]$ stop=`head -$i regions.txt | awk '{print $4}'`
[lg45@dev64-mgmt ~]$ echo $stop
26315393 8441168 11592811 26315362 123286509 27802564 42911309
[lg45@dev64-mgmt ~]$

Now i am trying to loop through file #2 (format as above) with a statement such as this....

awk '{ if($3>$start'$$3<'$stop')print$0}'

But i think there is something wrong with the syntax and i am having trouble figuring out how to write the loop
Does that make sense??